Question

The container is fitted with a piston so that the volume can change. When the gas is heated at constant pressure, it expands to a volume of 25 L. What is the temperature of the gas in kelvins?

Answer 1

Answer:

$T_{2}$ =$\frac{25T_{1}}{V_{1}}$

where

$V_{1}$ is initial volume in liters

$T_{1}$ is initial temperature in kelvins

Explanation:

Let the initial volume be $V_{1}$ and the initial temperature be  $P_{1}$

Now by ideal gas law

$\frac{P_{1}V_{1}}{T_{1}}=nR..............(i)$

Similarly let

$V_{2}$ be final volume

$T_{2}$ be the final volume

thus by ideal gas law we again have

$\frac{P_{2}V_{2}}{T_{2}}=nR..............(ii)$

Equating i and ii we get

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

For system at constant pressure the above expression reduces to

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

Solving for $T_{2}$ we get

$T_{2}$ =$\frac{25T_{1}}{V_{1}}$

where

$V_{1}$ is initial volume in liters

$T_{1}$ is initial temperature in kelvins