Question

A sample of an ideal gas has a volume of 2.28 L at 2.80×102 K and 1.12 atm. Calculate the pressure when the volume is 1.27 L and the temperature is 304 K.

Answer 1

Answer: The pressure when the volume and temperature has changed is 2.18 atm

Explanation:

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=1.12atm\\V_1=2.28L\\T_1=2.80\times 10^2K=280K\\P_2=?atm\\V_2=1.27L\\T_2=304K$

Putting values in above equation, we get:

$\frac{1.12atm\times 2.28L}{280K}=\frac{P_2\times 1.27L}{304K}\\\\P_2=2.18atm$

Hence, the pressure when the volume and temperature has changed is 2.18 atm