We have that for the Question "What is the rate constant at 645 K?" it can be said that the rate constant at 645 K is
From the question we are told
Generally the equation for the Arrhenius equation is mathematically given as
[tex]ln(\frac{k2}{k1})=\frac{E}{R}(\frac{1}{t_1}-\frac{1}{t_2})[/tex]
Therefore
[tex]ln(\frac{k2}{k1})=\frac{E}{R}(\frac{1}{t_1}-\frac{1}{t_2})\\\\ln(\frac{k2}{3.52*10^{-7}})=\frac{186}{8.314}(\frac{1}{555}-\frac{1}{645})[/tex]
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