Question

A lawn sprinkler is located at the corner of a yard. The sprinkler is set to rotate through 90 and project water out 52 feet. What is the area (rounded to three significant digits) of the yard watered by the sprinkler?

Answer 1

Answer:

2122.64 ft^2

Explanation:

The sprinkler turns by 90 degree, it means it covers the one fourth part of a circular area.

Area covered = $\frac{\pi r^{2}}{4}$

Where, r be the radius of the circular part.

r = 52 feet

Area = $\frac{3.14\times 52^{2}}{4}$

Area = 2122.64 ft^2