If the diffusion coefficient doubles, and the average diffusion distance across a membrane remains the same, what can be said about the time it takes to cross the membrane g

Respuesta :

Answer:

time taken will be halved

Explanation:

we have

[tex]t=\frac{x^{2}}{2D}[/tex]   ..................(1)

where

t = time elapsed since diffusion began

[tex]x^{2}[/tex] = mean distance traveled by the diffusion solute

D = Diffusion coefficient

now, according to the conditions given in the question

when, diffusion coefficient (D) doubles i.e D' = 2D

Average diffusion distance remains same i.e [tex]x' = x[/tex]

substituting the values in the equation we get

[tex]t=\frac{x'^{2}}{2D'}[/tex]

or

[tex]t=\frac{x^{2}}{2(2D)}[/tex]

or

[tex]t=\frac{x^{2}}{4D}[/tex] ...............(2)

hence, on comparing equation (1) and (2) we can say that the time taken will be halved when the diffusion coefficient doubles and the mean distance traveled remains the same

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