Question

A wind turbine has 12,000 kg blades that are 37 m long. The blades spin at 24 rpm .If we model a blade as a point mass at the midpoint of the blade, what is the inward force necessary to provide each blade's centripetal acceleration

Answer 1

Answer:

$F_c = 1.4 \times 10^6 N$

Explanation:

As we know

$f = 24 rpm$

so we will have

$f = 24 \frac{1}{60} hz = 0.4hz$

now angular frequency is given as

$\omega = 2\pi f$

$\omega = 0.8\pi$

Now the inwards is given as centripetal force

$F_c = m\omega^2 r$

$F_c = (12000)(0.8\pi)^2(\frac{37}{2})$

$F_c = 1.4 \times 10^6 N$