Answer:
1.27 x 10⁵ L
Explanation:
V₁ = initial volume = 14100 L
V₂ = final volume = ?
P₁ = initial pressure = 745 torr
P₂ = final pressure = 63.1 torr
T₁ = initial temperature = 21 °C = 21 + 273 = 294 K
T₂ = final temperature = - 48 °C = - 48 + 273 = 225 K
Using the equation
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
[tex]\frac{(745)(14100)}{294} = \frac{(63.1)V_{2}}{225}[/tex]
[tex]V_{2}[/tex] = 1.27 x 10⁵ L