A square wire, 20 cm on the side, moves at constant speed parallel to the xy-plane into a region where there is a uniform magnetic field = (0.1 T) .The induced electric current in the coil is 10 mA and its resistance is 10Ω. What is the speed of the wire?

Respuesta :

Answer:

The speed of the wire is 5 m/s.

Explanation:

Given that,

Length = 20 cm

Magnetic field = 0.1 T

Current = 10 mA

Resistance [tex]R= 10\Omega[/tex]

We need to calculate the  speed of the wire

Using formula of emf

[tex]\epsilon=Bvl[/tex]

Using formula of current

[tex]I=\dfrac{\epsilon}{R}[/tex]

Put the value of [tex]\epsilon[/tex] into the formula of current

[tex]I=\dfrac{Bvl}{R}[/tex]

[tex]v=\dfrac{IR}{Bl}[/tex]

[tex]v=\dfrac{10\times10^{-3}\times10}{0.1\times20\times10^{-2}}[/tex]

[tex]v= 5\ m/s[/tex]

Hence, The speed of the wire is 5 m/s.

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