Answer:
10
Explanation:
(r) = <10 cos 6t, 10 Sin 6t>
The distance traveled by the object is the magnitude of vector r.
The magnitude of vector r is given by
[tex]r = \sqrt{(10 Cos 6t)^{2}+(10 Sin 6t)^{2}}[/tex]
[tex]r =10 \sqrt{(Cos^{2} 6t)+(Sin^{2} 6t)[/tex]
r = 10