Question

How many line ofoutput will be displayed by the following program fragment?
i=0;
do
{
for(j=0;j<4;j=j+1)
printf("%d\n",i+j);
i=i+1;
}
while(i<5);
A. 0
B. 7
C. 9
D. 16
E. 20

Answer 1

Answer:

Hi!

Let's make a quick debug of the code:

i    j   Output

0+0 =  0  

0+1 =    1

0+2 =  2

0+3 =  3

1+0 =  1 

1+1 =    2

1+2 =  3

1+3 =  4

2+0 =  2  

2+1 =    3

2+2 =  4

2+3 =  5

3+0 =  3  

3+1 =   4

3+2 =  5

3+3 =  6

4+0 =  4  

4+1 =   5

4+2 =  6

4+3 =  7

The total outputs is 20.

Explanation:

In the first iterations of the loop for the final value of the i is 1 and the final condition to stop of the do while is (i < 5) , so the iteration of for continues many times until  i break the condition.  

(5*4 = 20)

And after that you get 20 outputs.

I hope it's help you.