please help, I'd greatly appreciate it
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Your answer is=>
[tex] { \bold{ = > y - 3 = \frac{1}{2} (x + 6)}}[/tex]
[tex]{ \bold{ = > y - 3 = \frac{1x}{2} + \frac{6}{2} }}[/tex]
[tex]{ \bold{ = > y - 3 = \frac{1x}{2} + 3 }}[/tex]
[tex]{ \bold{ = > y = \frac{1x}{2} + 3 + 3}}[/tex]
[tex]{ \bold{ = > y = \frac{1x}{2} + 6 }}[/tex]
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Answer:
The first one is in standard form and is equivalent to the given equation.
Step-by-step explanation:
Standard form of a line is ax+by=c.
There is only one choice like that so I hope they are equivalent.
Let's check:
[tex]y-3=\frac{1}{2}(x+6)[/tex]
To clear the fraction multiply both sides by 2:
[tex]2y-6=1(x+6)[/tex]
[tex]2y-6=x+6[/tex]
Add 6 on both sides:
[tex]2y=x+12[/tex]
Subtract x on both sides:
[tex]-x+2y=12[/tex]
Multiply both sides by -1:
[tex]x-2y=-12[/tex]
They are!