Answer:
0.8413 or 84.13%
Step-by-step explanation:
Given : The mean is 72 inches and the standard deviation is 15 inches
To Find : What is the probability that in a randomly selected year, the snowfall was less than 87 inches
Solution:
Mean = [tex]\mu = 72[/tex]
Standard deviation = [tex]\sigma = 15[/tex]
Formula : [tex]z=\frac{x-\mu}{\sigma}[/tex]
We are supposed to find the probability that in a randomly selected year, the snowfall was less than 87 inches
So, x = 87
Substitute the values in the formula
[tex]z=\frac{87-72}{15}[/tex]
[tex]z=1[/tex]
Now to find P(z<87) refer the z table
P(Z<87)=0.8413 = 84.13%
So, the probability that in a randomly selected year, the snowfall was less than 87 inches if the mean is 72 inches and the standard deviation is 15 inches is 0.8413 or 84.13%