Question

Identify the zeros of f(x) =(x+9)(x - 4)(6x + 1)

Answer 1

Answer:

The zeros of the function are $x=-9, x=-1/6, x=4$

Step-by-step explanation:

we know that

The zeros of the function or the x-intercepts are the values of x when the value of the function is equal to zero

so

For f(x)=0

we have

$(x+9)(x-4)(6x+1)=0$

Find the first zero

$(x+9)=0$ -----> $x=-9$

Find the second zero

$(x-4)=0$ -----> $x=4$

Find the third zero

$(6x+1)=0$ -----> $x=-1/6$

therefore

The zeros of the function are $x=-9, x=-1/6, x=4$