Answer:
a). The potential is highest at the center of the sphere
Explanation:
We k ow the potential of a non conducting charged sphre of radius R at a point r < R is given by
[tex]E=\left [ \frac{K.Q}{2R} \right ]\left [ 3-(\frac{r}{R})^{2} \right ][/tex]
Therefore at the center of the sphere where r = 0
[tex]E=\left [ \frac{K.Q}{2R} \right ]\left [ 3-0 \right ][/tex]
[tex]E=\left [ \frac{3K.Q}{2R} \right ][/tex]
Now at the surface of the sphere where r = R
[tex]E=\left [ \frac{K.Q}{2R} \right ]\left ( 3-1 \right )[/tex]
[tex]E=\left [ \frac{2K.Q}{2R} \right ][/tex]
[tex]E=\left [ \frac{K.Q}{R} \right ][/tex]
Now outside the sphere where r > R, the potential is
[tex]E=\left [ \frac{K.Q}{r} \right ][/tex]
This gives the same result as the previous one.
As [tex]r\rightarrow \infty , E\rightarrow 0[/tex]
Thus, the potential of the sphere is highest at the center.