Respuesta :

[tex]\bf \textit{height or altitude of an equilateral triangle}\\\\ h=\cfrac{s\sqrt{3}}{2}~~ \begin{cases} s=\stackrel{length~of}{a~side}\\ \cline{1-1} s=8\sqrt{3} \end{cases}\implies h=\cfrac{8\sqrt{3}\cdot \sqrt{3}}{2}\implies h=\cfrac{8\sqrt{3^2}}{2} \\\\\\ h=4\cdot 3\implies h=12[/tex]

Answer:

E. 12

Step-by-step explanation:

le ✨Ap3x✨

ACCESS MORE