Question

A spinner has 20 equally sized sections, 8 of which are yellow and 12 of which are blue. The spinner is spun and, at the same time, a fair coin is tossed. What is the probability that the spinner lands on blue and the coin is tails?

Answer 1

Answer:

3/10

Step-by-step explanation:

These two events are independent, so the overall probability is the product of the individual probabilities.

12 blue sections out of 20

p(blue) = 12/20 = 3/5

There is an equal probability of the coin landing on heads or tails.

p(tails) = 1/2

p(blue & tails) = 3/5 * 1/2 = 3/10

Answer 2

The probability of an event is defined as the ratio between the number of instances favorable towards the occurrence, that is, the number of those events in the subset of the sample space describing the occurrence, to the overall number of cases.

Since these are two distinct occurrences:

The probability that its spinner will land on yellow, and tossed coins, will be tails:

=The probability that the spinner will land on blue is high ×The probability that a tail will occur

$=(\frac{12}{20})\times (\frac{1}{2})\\\\=\frac{12}{40}\\\\=\frac{3}{10}\\ \\ =0.3$

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