Which is the graph of the equation y-1=2/3(x-3)?
PLEASE ANSWER ASAP
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Answer:
Graph #1
Step-by-step explanation:
Compare your
y - 1 = (2/3)(x - 3) to
y - k = m(x - h). We see that k = 1 and h = 3.
Thus, (1, 3) is a point on the graph. This matches Graph #1.
Note: Graph #1 and Graph #3 appear to be the same. Why?
The graph of the equation is:
Graph 1
The equation is given by:
[tex]y-1=\dfrac{2}{3}\times (x-3)[/tex]
Now, we will see the point through which the graph passes through.
when x=3 we have:
[tex]y-1=\dfrac{2}{3}\times (3-3)\\\\i.e.\\\\y-1=\dfrac{2}{3}\times 0\\\\i.e.\\\\y-1=0\\\\i.e.\\\\y=1[/tex]
i.e. the graph passes through (3,1)
and also when x= -3 we have:
[tex]y-1=\dfrac{2}{3}\times (-3-3)\\\\i.e.\\\\y-1=\dfrac{2}{3}\times -6\\\\i.e.\\\\y-1=2\times -2\\\\i.e.\\\\y-1=-4\\\\i.e.\\\\y=-4+1\\\\i.e.\\\\y=-3[/tex]
i.e. the graph passes through (-3,-3)
The graph which satisfies these two points is: Graph 1