Question

What is the midpoint of CD?
5
4
-3
-2
-1, 1
1
2
3
4
5 x
D(4,-1)
C(-3,-4)

Answer 1

Answer:

$\large\boxed{M_{CD}\left(\dfrac{1}{2},\ -\dfrac{5}{2}\right)}$

Step-by-step explanation:

The formula of a midpoint of a segment AB with endpoints at A(x₁, y₁) and B(x₂, y₂):

$M_{AB}\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

We have the points C(-3, -4) and D(4, -1).

Substitute:

$M_{CD}(x,\ y)\\\\x=\dfrac{-3+4}{2}=\dfrac{1}{2}\\\\y=\dfrac{-4+(-1)}{2}=\dfrac{-5}{2}=-\dfrac{5}{2}$