Question

what are the zeros of the function below ? check all that apply. F(x)= 5(x+2)/3(x-1)(x+7)

Answer 1

Answer:

-2 is a zero if your function is $F(x)=\frac{5(x+2)}{3(x-1)(x+7)}$

Please correct me if I'm wrong.

Step-by-step explanation:

Assuming you meant $F(x)=\frac{5(x+2)}{3(x-1)(x+7)}$

the zeros are what makes the numerator 0 (any zeros of the top that are also zeros of the bottom should be excluded).

Anyways we just need to find when 5(x+2) is 0.

5(x+2)=0

Divide by 5 on both sideS:

x+2=0

Subtract 2 on both sides:

x=-2

And -2 doesn't make the bottom 0.

Checking to see :   3(-2-1)(-2+7)=3(-3)(5)=-9(5)=-45 (not 0).

So F has zero -2.

Answer 2

The zeroes of the function f(x)= 5(x + 2) / 3(x - 1)(x + 7) will be negative 2.

What is an asymptote?

An asymptote is a line that constantly reaches a given curve but does not touch at an infinite distance.

The function is given below.

f(x)= 5(x + 2) / 3(x - 1)(x + 7)

Then the value of the function is not defined at 1 and negative 7.

Then the zeroes of the function will be

x + 2 = 0

     x = -2

The zeroes of the function will be negative 2.

More about the asymptote link is given below.

https://brainly.com/question/17767511

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