Question

Consider the relationship 3r+2t=18

A. write the relationship as a function r=f(t)

B. Evaluate f(-3)

C. solve f(t)= 2

Answer 1

Answer and Explanation:

Given : Consider the relationship $3r+2t=18$

To find :

A.  Write the relationship as a function r=f(t)

B. Evaluate f(-3)

C. Solve f(t)= 2

Solution :

A) To write the relationship as function r=f(t) we separate the r,

$3r+2t=18$

Subtract 2t both side,

$3r=18-2t$

Divide by 3 both side,

$r=\frac{18-2t}{3}$

The function is $f(t)=\frac{18-2t}{3}$

B) To evaluate f(-3) put t=-3

$f(-3)=\frac{18-2(-3)}{3}$

$f(-3)=\frac{18+6}{3}$

$f(-3)=\frac{24}{3}$

$f(-3)=8$

C) Solve for f(t)=2

$\frac{18-2t}{3}=2$

$18-2t=6$

$2t=12$

$t=\frac{12}{2}$

$t=6$

Answer 2

The value of f(-3), to write the relationship as a function (r = f(t)) and to solve the (f(t) = 2) expression, arithmetic operations can be use. Refer the below calculation for better understanding.

Given :

3r + 2t = 18

A) 3r = 18 - 2t

$r = 6-\dfrac{2t}{3}$   ---- (1)

where,   $\rm f(t)=6-\dfrac{2t}{3}$   ----- (2)

B)   $r = 6-\dfrac{2t}{3}$

Given that f(-3) imply that t = -3. So from equation (2) we get

f(-3) = 8

C) Given that f(t) = 2. So from equation (2) we get,

$2 = 6 -\dfrac{2t}{3}$

2t = 12

t = 6

The value of f(-3), to write the relationship as a function (r = f(t)) and to solve the (f(t) = 2) expression, arithmetic operations can be use.

For more information, refer to the link given below:

https://brainly.com/question/21114745