Question

A current of 0.2 A flows through a 3 m long wire that is perpendicular to a 0.3 T magnetic field. What is the magnitude of the force on the wire in units of newtons?

Answer 1

Answer:

Magnetic force, F =  0.18 N

Explanation:

It is given that,

Current flowing in the wire, I = 0.2 A

Length of the wire, L = 3 m

Magnetic field, B = 0.3 T

It is placed perpendicular to the magnetic field. We need to find the magnitude of force on the wire. It is given by :

$F=ILB\ sin\theta$

$F=0.2\ A\times 3\ m\times 0.3\ T\ sin(90)$

F = 0.18 N

So, the magnitude of force on the wire is 0.18 N. Hence, this is the required solution.