Answer:
The internal energy is 73.20 J.
Explanation:
Given that,
Weight of helium = 86 mg
Temperature = 0°C
We need to calculate the internal energy
Using formula of internal energy
[tex]U =nc_{v}T[/tex]
Where, [tex]c_{v}[/tex] = specific heat at constant volume
He is mono atomic.
So, The value of [tex]c_{v}= \dfrac{3}{2}R[/tex]
now, 1 mole of Helium = 4 g helium
n =number of mole of the 86 mg of helium
[tex]n = \dfrac{86\times10^{-3}}{4}[/tex]
[tex]n =2.15\times10^{-2}\ mole[/tex]
T = 0°C=273 K
Put the value into the formula
[tex]U = 2.15\times10^{-2}\times\dfrac{3}{2}\times8.314\times273[/tex]
[tex]U = 73.20\ J[/tex]
Hence, The internal energy is 73.20 J.