Question

a triangular course for a canoe race is marked with buoys. the first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi. how long is the race?

(the numbers are fractions)

Answer 1

Answer:

1 1/5 mi

Step-by-step explanation:

We need to add the three legs together

3/10 + 1/2 + 2/5

The common denominator is 10

3/10  =3/10

1/2 *5/5 = 5/10

2/5 *2/2 =4/10

3/10 + 5/10+4/10 = 12/10

10/10 = 10/10+2/10 = 1+2/10  = 1 1/5 mi

Answer 2

Answer:

Length of race = 1.2 miles

Step-by-step explanation:

Length of race is given by the perimeter of triangle.

Refer the given figure.

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

$\texttt{Perimeter =}\frac{3}{10}+\frac{1}{2}+\frac{2}{5}=\frac{3}{10}+\frac{5}{10}+\frac{4}{10}=\frac{3+5+4}{10}\\\\\texttt{Perimeter =}\frac{12}{10}=1.2 miles$

Length of race = 1.2 miles