Answer:
Option B is the correct answer.
Explanation:
We have resistance [tex]R=\frac{\rho l}{A}[/tex]
The resistance of wire B is four times that of wire A
[tex]R_B=4R_A\\\\\frac{\rho_B l_B}{A_B}=4\times \frac{\rho_A l_A}{A_A}\\\\\frac{A_A}{A_B}=4\\\\\frac{\pi r_A^2}{\pi r_B^2}=4\\\\\frac{r_A}{r_B}=2[/tex]
Option B is the correct answer.