Answer:
Capacitive reactance is 132.6 Ω.
Explanation:
It is given that,
Capacitance, [tex]C=20\ \mu F=20\times 10^{-6}\ F=2\times 10^{-5}\ F[/tex]
Voltage source, V = 20 volt
Frequency of source, f = 60 Hz
We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :
[tex]X_C=\dfrac{1}{2\pi fC}[/tex]
[tex]X_C=\dfrac{1}{2\pi \times 60\ Hz\times 2\times 10^{-5}\ F}[/tex]
[tex]X_C=132.6\ \Omega[/tex]
So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.