Respuesta :

Answer:

Capacitive reactance is 132.6 Ω.

Explanation:

It is given that,

Capacitance, [tex]C=20\ \mu F=20\times 10^{-6}\ F=2\times 10^{-5}\ F[/tex]

Voltage source, V = 20 volt

Frequency of source, f = 60 Hz

We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :

[tex]X_C=\dfrac{1}{2\pi fC}[/tex]

[tex]X_C=\dfrac{1}{2\pi \times 60\ Hz\times 2\times 10^{-5}\ F}[/tex]

[tex]X_C=132.6\ \Omega[/tex]

So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.