Question

What is the magnitude (in Newtons) of the force a 796-uC charge exerts on a 481-nC charge 23.1-cm away? 2 pts Question 5 A proton is released in a uniform electric field, and it experiences an electric force of 6.9x10-15-N toward the south. What is the magnitude (in N/C) of the electric field?

Answer 1

Answer:

(a) 64.58 N

(b) 43125 N/C

Explanation:

(a) q1 = 796 uC = 796 x 10^-6 C, q2 = 481 nC = 481 x 10^-9 C,

r = 23.1 cm = 0.231 m

Force, F = k q1 q2 / r^2

F = (9 x 10^9 x 796 x 10^-6 x 481 x 10^-9) / (0.231)^2

F = 64.58 N

(b) F = 6.9 x 10^-15 N

E = F / q

E = (6.9 x 10^-15) / (1.6 x 10^-19) = 43125 N/C