[tex]|\Omega|=6^6\\|A|=6\cdot 5^5\\\\P(A)=\dfrac{6\cdot5^5}{6^6}=\dfrac{5^5}{6^5}=\dfrac{3125}{7776}\approx40.2\%[/tex]
The probability that a face with a 6 comes up exactly once will be 0.40.
Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
A number cube has 6 faces, numbered from 1 to 6.
If the cube is rolled six times.
Then the probability that a face with a 6 comes up exactly once will be
The total number of the event will be
Total event = 6⁶
Total event = 46656
Favorable event = 6 x 5⁵
Favorable event = 18750
Then the probability will be
P = 18750 / 46656
P = 3125 / 7776
P = 0.40
More about the probability link is given below.
https://brainly.com/question/795909
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