slope intercept form of equation of a line that passes through (-3,8) y=-2/3x+6 what is the point slope equation for this line???

Respuesta :

gmany

Answer:

[tex]\large\boxed{y-8=-\dfrac{2}{3}(x+3)}[/tex]

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

We have the equation of a line in the slope-intercept form

[tex]y=-\dfrac{2}{3}x+6\Rightarrow m=-\dfrac{2}{3}[/tex]

and the point (-3, 8).

Substitute:

[tex]y-8=-\dfrac{2}{3}(x-(-3))\\\\y-8=-\dfrac{2}{3}(x+3)[/tex]