Answer:
Step-by-step explanation:
The trig identities are helpful for this.
sin² θ = 1 - cos² θ = 1 -(1/6)² = 35/36
sin θ = (√35)/6 . . . . . . take the square root
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tan² θ = sec² θ -1 = (1/cos² θ) -1 = 6² -1 = 35
tan θ = √35 . . . . . . . . . take the square root