Respuesta :
Answer:
99.63 kg
Explanation:
From the force diagram
N = normal force on the worker from the surface of the roof
f = static frictional force = 560 N
θ = angle of the slope = 35
m = mass of the worker
W = weight of the worker = mg
W Cosθ = Component of the weight of worker perpendicular to the surface of roof
W Sinθ = Component of the weight of worker parallel to the surface of roof
From the force diagram, for the worker not to slip, force equation must be
W Sinθ = f
mg Sinθ = f
m (9.8) Sin35 = 560
m = 99.63 kg
The mass of the worker will be 99.63 Kg.It id denoted by m and its unit is Kg.
What is work?
Work is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work may be zero, positive and negative.it depend on the direction of body displaced . if the body is displaced in the same direction of force it will be positive.
While if the displacement is in the opposite direction of force applied the work will be negative work . if their is no displacement of the body the work done will be zero.
The given data in the problem is;
N is the normal force on the worker from the surface of the roof
f is the static frictional force = 560 N
θ is the angle of the slope = 35°
m is the mass of the worker=?
W = weight of the worker = mg
If the weight is resolved in the two components;
W Cosθ is the Component of the weight of worker perpendicular to the surface of roof
W Sinθ is the Component of the weight of worker parallel to the surface of roof
In order to prevent the worker from slipping the friction force must be balanced by;
[tex]W Sin\theta = f\\mg Sin\theta = f\\ m (9.8) Sin35^0 = 560\\m = 99.63 kg[/tex]
Hence he mass of the worker will be 99.63 Kg
To learn more about the work refer to the link ;
https://brainly.com/question/3902440
