Question

multiply (3x^2-2x)(2x^2+3x-1)​

Answer 1

Answer:

$\large\boxed{(3x^2-2x)(2x^2+3x-1)==6x^4+5x^3-8x^2+2x}$

Step-by-step explanation:

Use the distributive property and $(a^n)(a^m=)=a^{n+m}$

$(3x^2-2x)(2x^2+3x-1)\\\\=(3x^2)(2x^2)+(3x^2)(3x)+(3x^2)(-1)+(-2x)(2x^2)+(-2x)(3x)+(-2x)(-1)\\\\=6x^4+9x^3-3x^2-4x^3-6x^2+2x\qquad\text{combine like terms}\\\\=6x^4+(9x^3-4x^3)+(-3x^2-5x^2)+2x\\\\=6x^4+5x^3-8x^2+2x$

Answer 2

multiplication of  (3x^2-2x)(2x^2+3x-1)​ is 6X⁴+5X³-9x²+2X

What are polynomials?

• A polynomial expression is an expression that can be built from constants and symbols.
• Polynomials are algebraic expressions that comprise exponents which can be added, subtracted, or multiplied.
• Polynomials are of different types.
• Monomial- Linear equations (A monomial is a polynomial with one term)
• Binomia- quadratic equation (A binomial is a polynomial with two, unlike terms).

CALCULATION:-

⇒(3X²-2X)(2X²+3X-1)

⇒6X⁴+9X³-3X²-4X³-6X²+2X

⇒ 6X⁴+5X³-9x²+2X  (answer)

Learn more about polynomials here:-https://brainly.com/question/2833285

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