Answer:
The resistance added to this coil is 0.04 ohm in parallel.
Explanation:
Given that,
Current I'= 0.5 A
Resistance R= 20 ohm
Deflection I= 1 mA
We need to calculate the resistance
Using ohm's law
[tex]V = I R[/tex]
Where,
V = voltage
I =current
R = resistance
V is constant so ,
Therefore,
I R=I'R'
[tex]R'=\dfrac{I}{I'}\times R[/tex]
[tex]R'=\dfrac{0.001}{0.5}\times20[/tex]
[tex]R'=0.04\ \Omega[/tex]
Hence, The resistance added to this coil is 0.04 ohm in parallel.