Answer:
Part a)
charge through the battery is
[tex]Q = 9.72 \times 10^5 C[/tex]
Part b)
Maximum current is
i = 386 A
Explanation:
Part a)
As we know that the rating of battery is given as
[tex]R = 270 A h[/tex]
here we also know that the charge given by the battery is same as the capacity of the battery
so we will have
[tex]Q = i t[/tex]
[tex]Q = (270 A)(3600 s)[/tex]
[tex]Q = 9.72 \times 10^5 C[/tex]
Part b)
Now we know that current in the wire is given by
[tex]i = \frac{Q}{t}[/tex]
now plug in all values in it
[tex]i = \frac{9.72 \times 10^5}{42\times 60}[/tex]
[tex]i = 386 A[/tex]