Respuesta :
Answer:
[tex]\frac{1}{3}\ in[/tex]
Step-by-step explanation:
we have
[tex]a(n)=9(\frac{1}{3})^{n-1}[/tex]
For n=4
substitute
[tex]a(4)=9(\frac{1}{3})^{4-1}[/tex]
[tex]a(4)=9(\frac{1}{3})^{3}[/tex]
[tex]a(4)=9(\frac{1}{27})[/tex]
[tex]a(4)=\frac{1}{3}\ in[/tex]