Question

The velocity field of a steady flow is given as V=(U0+bx)i?b y j , where U0 and b are constant. Find the acceleration in the x- and y-directions if U0=1m/ s and b=0.3m .

Answer 1

Explanation:

The velocity field o a steady flow is given by :

$V=(U_o+bx)i$

Where

U₀ and b are constant

We know that, the acceleration is given by :

$a=\dfrac{dV}{dt}$

$a=\dfrac{d((U_o+bx)i)}{dt}$

a = b i

a = 0.3 m/s²

So, acceleration corresponding to this velocity is 0.3 m/s². Hence, this is the required solution.