Question

A length change - 0.18 m will occur for an object that is L- 80 m long, If the coeffcient of thermal expansion is12 x 106/C and if the original temperature is 83 C, find the final temperature.

Answer 1

Answer:

The final temperature is 270.5°C

Explanation:

Given that,

Change length = 0.18 m

Length = 80 m

Coefficient of thermal expansion $\alpha=12\times10^{-6}\ C^{\circ}$

Temperature = 83°C

We need to calculate the final temperature

Using formula thermal expansion

$\delta l=l\alpha\times\delta t$

Where, $\Delta l$ =change in length

$\Delta t$ = change in temperature

$\alpha$ = coefficient of thermal expansion

Put the value into the formula

$0.18=80\times12\tmes10^{6}\times(T_{f}-T_{i})$

$T_{f}-83=\dfrac{0.18}{80\times12\times10^{-6}}$

$T_{f}=187.5+83=270.5^{\circ} C$

Hence, The final temperature is 270.5°C