Answer:
So the intensity of the light be smaller in second case with the polarizers at 90 degree with the vertical
Explanation:
When two polarizers are arranged at 45 degree and 90 degree in series
so here the intensity of light coming out of the polarizers is given as
[tex]I_1 = I_ocos^45[/tex]
[tex]I_1 = \frac{I_0}{2}[/tex]
now for second polarizer we have
[tex]I_2 = I_1 cos^2(90 - 45)[/tex]
[tex]I_2 = (\frac{I_0}{2})\frac{1}{2}[/tex]
[tex]I_2 = \frac{I_0}{4}[/tex]
now in other case when two polarizers are inclined 90 degree to the vertical
[tex]I = I_ocos^290 = 0[/tex]
so final intensity in second case will be ZERO
So the intensity of the light be smaller in second case with the polarizers at 90 degree with the vertical