Answer:
Option B is the correct answer.
Explanation:
Speed of car = 70mph [tex]=70\times \frac{1609}{3600}=31.28m/s[/tex]
Deceleration of car = 2 m/s²
We have equation of motion
v = u + at
0 = 31.28 - 2 t
t = 15.64 seconds.
We also have
[tex]s=ut+\frac{1}{2}at^2=31.28\times 15.64-\frac{1}{2}\times 2\times 15.64^2=244.70m[/tex]
Option B is the correct answer.