Question

A Raman line is observed at 4768.5 À, when acetylene was irradiated by 4358.3 A radiation, Calculate the equilibrium vibrational frequency that causes the shift.

Answer 1

Answer:

The equilibrium vibrational frequency that causes the shift is $0.56\times10^{14}\ Hz$

Explanation:

Given that,

Wavelength of Raman line $\lambda'=4768.5\ A$

Wavelength $\lambda=4358.3\ A$

We need to calculate the frequency

Using formula of frequency

$f =\dfrac{c}{\lambda}$

For 4748.5 A

The frequency is

$f'=\dfrac{3\times10^{8}}{4748.5\times10^{-10}}$

$f' =6.32\times10^{14}\ Hz$

For 4358.3 A

The frequency is

$f=\dfrac{3\times10^{8}}{4358.3\times10^{-10}}$

$f=6.88\times10^{14}\ Hz$

We need to calculate the shift

$\Delta f=f-f'$

$\Delta f=(6.88-6.32)\times10^{14}\ Hz$

$\Delta f=0.56\times10^{14}\ Hz$

Hence, The equilibrium vibrational frequency that causes the shift is $0.56\times10^{14}\ Hz$