Question

A 3500-kg statue is placed on top of a cylindrical concrete (Y = 2.3 times 10^10 N/m^2) stand. The stand has a cross-sectional area of 7.3 times 10^-2 m^2 and a height of 1.8m. By how much the statue compress the stand?

Answer 1

Answer:

The statue compress the stand by 3.68 x 10⁻⁵ m.

Explanation:

Change in length

            $\Delta L=\frac{PL}{AY}$

Load, P = 3500 x 9.81 = 34335 N

Young's modulus, Y = 2.3 x 10¹⁰ N/m²

Area, A = 7.3 x 10⁻² m²

Length, L = 1.8 m

Substituting

         $\Delta L=\frac{PL}{AE}=\frac{34335\times 1.8}{7.3\times 10^{-2}\times 2.3\times 10^{10}}=3.68\times 10^{-5}m$

The statue compress the stand by 3.68 x 10⁻⁵ m.