Respuesta :
[tex]\text{Use pythagorean theorem}[/tex]
[tex]$a^2 + b^2 = c^2 \longrightarrow a^2 +6^2=9^2 \longrightarrow a^2 =45\longrightarrow a =6.7082\longrightarrow a = 6.71$[/tex]
[tex]\textbf{a = 6.71}[/tex]
This is a right triangle and to solve this you must use Pythagorean theorem:
[tex]a^{2} +b^{2} =c^{2}[/tex]
a and b are the legs (the sides that form a perpendicular/right angle)
c is the hypotenuse (the side opposite the right angle)
In this case...
a = 6
b = x
c = 9
^^^Plug these numbers into the theorem
[tex]6^{2} +x^{2} =9^{2}[/tex]
simplify
36 + [tex]x^{2}[/tex] = 81
Now bring 36 to the right side by subtracting 36 to both sides (what you do on one side you must do to the other). Since 36 is being added on the left side, subtraction (the opposite of addition) will cancel it out (make it zero) from the left side and bring it over to the right side.
36 - 36 + [tex]x^{2}[/tex] = 81 - 36
0 + [tex]x^{2}[/tex] = 45
[tex]x^{2}[/tex] = 45
To remove the square from x take the square root of both sides to get you...
x = √45
x ≈ 6.71
(choice A)
Hope this helped!
~Just a girl in love with Shawn Mendes