Respuesta :
Answer:
Option d. the initial amount of money placed in the savings account
Step-by-step explanation:
we have
[tex]f(x)=3,005(1+0.03)^{x}[/tex]
This is a exponential function of the form
[tex]f(x)=a(1+r)^{x}[/tex]
where
a is the initial value
r is the growth rate
(1+r) is the base
x is the number of years
f(x) is the amount of money in a savings account
In this problem we have
a=$3,005
r=0.03=3%
(1+r)=1.03
therefore
3,005 represent the initial value ( the amount of money for the value of x equal to zero)
Answer:
d. The initial amount of money placed in the savings account
Step-by-step explanation:
Given function that represents the amount of money after x years,
[tex]f(x)=3005(1+0.03)^x[/tex]
Which is an exponential growth function,
Since, in a growth function,
[tex]f(x)=ab^x[/tex]
a represents the initial value,
b is the growth rate per period,
x is the number of periods,
By comparing,
a = 3005,
Hence, 3005 must be represent the initial amount of money placed in the savings account,
Option 'd' is correct.