Question

The number of lattes sold daily by two coffee shops is shown in the table.


Shop A Shop B
55 45
52 42
56 57
48 48
57 11
30 10
45 46
41 43


Based on these data, is it better to describe the centers of distribution in terms of the mean or the median? Explain.

A: Mean for both coffee shops because the data distribution is symmetric

B: Median for both coffee shops because the data distribution is not symmetric


C:Mean for shop B because the data distribution is symmetric; median for shop A because the data distribution is not symmetric


B: Mean for shop A because the data distribution is symmetric; median for shop B because the data distribution is not symmetric




Please help I literally could not find this answer ANY where else
Very important

Answer 1

Answer:

D.

Step-by-step explanation:

The data is symmetric for Shop A but not for Shop B ( note the values 10 and 11 for Shop B which are a lot lower than the other values).

Mean for Shop A and Median for Shop B.

Answer 2

Answer:

The correct option is B.

Step-by-step explanation:

The number of lattes sold daily by two coffee shops is shown in the table.

The data set for shop A is

55, 52, 56, 48, 57, 30, 45, 41

Arrange the data in ascending order.

30, 41, 45, 48, 52, 55, 56, 57

Mean of shop A is

$Mean=\frac{\sum x}{n}=\frac{30+41+45+48+52+55+56+57}{8}=48$

$Median=\frac{(\frac{n}{2})th+(\frac{n}{2}+1)th}{2}=\frac{48+52}{2}=50$

The data set for shop B is

45, 42, 57, 48, 11, 10, 46, 43

Arrange the data in ascending order.

10, 11, 42, 43, 45, 46, 48, 57

Mean of shop A is

$Mean=\frac{\sum x}{n}=\frac{10+11+42+43+45+46+48+57}{8}=37.75$

$Median=\frac{(\frac{n}{2})th+(\frac{n}{2}+1)th}{2}=\frac{43+45}{2}=44$

Both data distribution are not symmetric, so it is better to describe the centers of distribution in terms of median for both coffee shops. Therefore the correct option is B.