Answer:
f = 6.912 E14 Hz
Explanation:
The speed of the wave is defined as
speed = wavelength*frequency
the frequency of the photon is defined as
f = speed / wavelength
f = 3 E8 m/s / 434 E-9 m
f = 6.912 E14 Hz
Answer:
Frequency, [tex]f=6.91\times 10^{14}\ Hz[/tex]
Explanation:
It is given that,
Wavelength, [tex]\lambda=434\times 10^{-9}\ m[/tex]
Speed of light, [tex]c=3\times 10^8\ m/s[/tex]
The frequency of photon can be calculated using following relation as :
[tex]c=f\times \lambda[/tex]
[tex]f=\dfrac{c}{\lambda}[/tex]
[tex]f=\dfrac{3\times 10^8\ m/s}{434\times 10^{-9}}[/tex]
[tex]f=6.91\times 10^{14}\ Hz[/tex]
So, the frequency of the photon is [tex]f=6.91\times 10^{14}\ Hz[/tex]. Hence, this is the required solution.
