Select the two values of x that are roots of this equation. (This is for apex by the way)
x^2-5x+5=0

Answer:
Step-by-step explanation:
Find the discriminant, b^2-4ac: Here a = 1, b = -5 and c = 5.
Then the discriminant is (-5)^2-4(1)(5) = 5, and so there are 2 real, different roots. The roots are:
-(-5) ±√5
x = ----------------, which correspond to answers A and C.
2(1)
The roots of the equation will be (5 - √5) / 2 and (5 + √5) / 2. Then the correct options are A and C.
The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2. Then we have
The quadratic equation is given below.
x² - 5x + 5 = 0
Then the root of the equation is given as
[tex]\rm x = \dfrac{ - (-5) \pm \sqrt{(-5)^2 - 4*1*5}}{2*1}\\\\x = \dfrac{5 \pm \sqrt{25-20}}{2}\\\\x = \dfrac{5 \pm \sqrt5}{2}\\\\x = \dfrac{5 - \sqrt5}{2}, \dfrac{5 + \sqrt5}{2}[/tex]
Thus, the correct options are A and C.
More about the quadratic equation link is given below.
https://brainly.com/question/2263981
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