Answer:
hello : a²b² =4
Step-by-step explanation:
2ײ + 3x - 4=0
The roots of this equation exist because (2)(-4)<0
note : a'x²+b'x +c' =0.......The roots of this equation : a and b
a×b = c'/a' a' =2 and b'=3 and c' = - 4
in this exercice ; a²b² = (ab)² = (c'/a')² = (-4/2)² = (-2)² =4
Answer:
4
Step-by-step explanation:
given a quadratic equation in standard form
y = ax² + bx + c = 0 : a ≠ 0
with roots α and β, then
the sum of the roots α + β = - [tex]\frac{b}{a}[/tex] and
the product of the roots αβ = [tex]\frac{c}{a}[/tex]
2x² + 3x - 4 = 0 ← is in standard form
with a = 2, b = 3 and c = - 4
αβ = [tex]\frac{-4}{2}[/tex] = - 2, hence
α²β² = (αβ)² = (- 2)² = 4
