Answer with explanation:
Given the differential equation
y''+y=0
The two function let
[tex]y_1= sint -cost[/tex]
[tex]y_2=sint+ cost[/tex]
Differentiate [tex]y_1 and y_2[/tex]
Then we get
[tex]y'_1= cost+sint[/tex]
[tex]y'_2=cost-sint[/tex]
Because [tex]\frac{\mathrm{d} sinx}{\mathrm{d} x} = cosx[/tex]
[tex]\frac{\mathrm{d}cosx }{\mathrm{d}x}= -sinx[/tex]
We find wronskin to prove that the function is independent/ fundamental function.
w(x)=[tex]\begin{vmatrix} y_1&y_2\\y'_1&y'_2\end{vmatrix}[/tex]
[tex]w(x)=\begin{vmatrix}sint-cost&sint+cost\\cost+sint&cost-sint\end{vmatrix}[/tex]
[tex]w(x)=(sint-cost)(cost-sint)- (sint+cost)(cost+sint)[/tex]
[tex]w(x)=sintcost-sin^2t-cos^2t+sintcost-sintcost-sin^2t-cos^2t-sintcost[/tex]
[tex]w(x)=-sin^2t-cos^2t[/tex]
[tex]sin^2t+cos^2t=1[/tex]
[tex]w(x)=-2\neq0[/tex]
Hence, the given two function are fundamental set of function on R.