Question

A satellite weighs 104 N at ground control. What best approximates the acceleration it experiences in orbit at an altitude of twice the earth's radius ifFpa = GME2thm, where r is the distance separating the centers of mass of the satellite and the Earth? O A. 111 m/s2 O B. 2.5 m/s O C. 1.1 m/s2 ○ D. 0 m/s

Answer 1

Answer:

$a_c = 1.1 m/s^2$

Explanation:

As we know that net force on the Satellite due to gravity will provide it centripetal force

so we can say here

$F_g = F_c$

$\frac{GMm}{r^2} = ma_c$

now we will have

acceleration given by the equation

$a_c = \frac{GM}{r^2}$

now we have

r = R + 2R = 3R

$a_c = \frac{GM}{9R^2}$

also we know that acceleration due to gravity on the surface of earth is given as

$g = \frac{GM}{R^2} = 9.8 m/s^2$

so the acceleration of satellite is given as

$a_c = \frac{9.8}{9} = 1.1 m/s^2$