Answer:
[tex]3.6*10^{4}\ joules[/tex] or [tex]36,000\ joules[/tex]
Step-by-step explanation:
Let
x -----> the energy in joules used by the CFL in one hour
we know that
using proportion
[tex]\frac{1}{3.6*10^{6}}\frac{kWh}{joules} =\frac{10^{-2}}{x}\frac{kWh}{joules}\\ \\x=(3.6*10^{6})(10^{-2})\\ \\x=3.6*10^{4}\ joules[/tex]
or
[tex]36,000\ joules[/tex]