ayaankhan7532 ayaankhan7532
  • 29-06-2019
  • Mathematics
contestada

d/dx(1+x^4+x^6/x^2+x+1)
A)2x+1
B)2x-1
C)2
D)0

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Shriacha5 Shriacha5
  • 29-06-2019

\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}

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